탐구자
이벤트

통찰.

비용: 2. XP: 4.
테스트 아이콘:

당신이 가지고 있는 단서 마다 (최대 3개), 아래 효과를 반복합니다.

당신이 위치한 장소의 조사자를 한 명 선택합니다. 그 조사자는 공포를 2만큼 회복하거나, 위협 영역에 있는 두려움 카드를 한 장 버립니다.

"나는 살아있는 가장 현명한 사람이다. 그 이유는 내가 하나를 알고 있기 때문이다. 그리고 그것은 내가 아무 것도 모르는 것을 의미한다."
- 플루토, 국가
Andreas Zafiratos
Return to the Path to Carcosa #3.
논리적 추론
Reviews

This seems like a great upgrade for multiplayer Carcosa campaigns, especially as run by Carolyn Fern...get 3 clues first, have everyone else join you on your space, then one action and 2 measly resources from you, and everyone on the square gets healing and resources. Using this early in Dim Carcosa in particular would really help.

Krysmopompas · 43
Yes, playing this card twice helped us to win the Dim Carcosa. Great card for multiplayer. — Trochomancy · 1

I have two questions about this card:

  • is it possibile to split the healing between more investigators? or do i have to target the same investigator with every "2 heal" chain?

  • is it possibile to split effects of card? example:(in case i have 2 clues ) healing 2 horrors to an investigator, and then remove a terror card ?

or do i have to choose only 1 effect and stick with that for all the clues i have?

Thanks

Rosco · 1
Yes, you can split the effects, that's why it says "for each clue you have" — Sassenach · 121
That could just be referring to the number of times you can perform a single action. "do it 3 times (i.e.)". It's not clear about the split. Since is a relatively new card (return to carcosa) i suppose there's no FAQ about this right? — Rosco · 1
Since it’s ‘for each clue, either’ you can split the effects as per your second bullet point. Re: your first ‘heal 2 from an investigator’ clear states ‘an’ then it’s pretty clear it can’t be split further. I could also interpret it as only being able to clear horror from one investigator total, but I think it’s intended to be read as ‘pick an investigator for each heal 2 chain.’ — Death by Chocolate · 428